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Author Question: Two point charges of +2.00 C and +4.00 C are at the origin and at the point x = 0.000 m, y = -0.300 ... (Read 33 times)

fasfsadfdsfa

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on: Oct 11, 2019

Question 1

Two +6.0-µC charges are placed at two of the vertices of an equilateral triangle having sides 2.0 m long. What is the electric potential at the third vertex, relative to infinity, due to these charges?
◦ 108 V
◦ 0 V
◦ 90 kV
◦ 27 kV
◦ 54 kV

Question 2

Two point charges of +2.00 μC and +4.00 μC are at the origin and at the point x = 0.000 m, y = -0.300 m, as shown in the figure. What is the electric potential due to these charges, relative to infinity, at the point P at x = 0.400 m on the x-axis? (k = 1/4πε0 = 8.99 × 109 N ∙ m2/C2)



◦ 15.7 kV
◦ 11.7 kV
◦ 36.0 kV
◦ 117 kV
◦ 56.0 kV
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Marked as best answer by fasfsadfdsfa on Oct 11, 2019

Gabe

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Reply #1 on: Oct 11, 2019
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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fasfsadfdsfa

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Reply 2 on: Oct 11, 2019
Gracias!

scottmt

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Reply 3 on: Yesterday
:D TYSM

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