Author Question: According to the following balanced reaction, how many moles of KOH will be formed from 5.44 moles ... (Read 171 times)

ahriuashd · **on:** Nov 18, 2019

Question 1

According to the following balanced reaction, how many moles of KO are required to exactly react with 5.44 moles of H2O?

4KO(s) + 2H2O(l) → 4KOH(s) + O2(g)

◦ 4.87 moles KO
◦ 8.33 moles KO
◦ 10.9 moles KO
◦ 16.7 moles KO
◦ 2.72 moles KO

Question 2

According to the following balanced reaction, how many moles of KOH will be formed from 5.44 moles of H2O? Assume an excess of KO.

4KO(s) + 2H2O(l) → 4KOH(s) + O2(g)

◦ 2.72 moles KOH
◦ 16.7 moles KOH
◦ 8.33 moles KOH
◦ 4.87 moles KOH
◦ 10.9 moles KOH

at · **Reply #1 on:** Nov 18, 2019

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