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Author Question: Determine the limiting reactant (LR) and the mass (in g) of nitrogen that can be formed from 50.0 g ... (Read 40 times)

Brittanyd9008

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on: Nov 18, 2019
Determine the limiting reactant (LR) and the mass (in g) of nitrogen that can be formed from 50.0 g N2O4 and 45.0 g N2H4. Some possibly useful molar masses are as follows: N2O4 = 92.02 g mol-1, N2H4 = 32.05 g mol-1.

N2O4(l) + 2N2H4(l) → 3N2(g) + 4H2O(g)

◦ LR = N2H4, 13.3 g N2 formed
◦ LR = N2O4, 45.7 g N2 formed
◦ No LR, 45.0 g N2 formed
◦ LR = N2H4, 59.0 g N2 formed
◦ LR = N2O4, 105 g N2 formed
Chemistry: A Molecular Approach (Canadian) ¦ Tro, Fridgen, Shaw ¦ 2nd Edition
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Marked as best answer by Brittanyd9008 on Nov 18, 2019

cuttiesgirl16

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Reply #1 on: Nov 18, 2019
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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Brittanyd9008

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Reply 2 on: Nov 18, 2019
Great answer, keep it coming :)

mammy1697

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Reply 3 on: Yesterday
Gracias!

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