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Author Question: Calculate the orbital for the hydrogen atom that contains an electron with an energy of -2.42 10-19 J. (Read 128 times)

jrubin

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Question 1

Calculate the energy of an electron in the orbital n = 6 of a hydrogen atom.
◦ 3.19 × 10-20 J
◦ -6.06 × 10-20 J
◦ 4.18 × 10-20 J
◦ -7.80 × 10-20 J
◦ -8.62 × 10-20 J

Question 2

Calculate the orbital for the hydrogen atom that contains an electron with an energy of -2.42 × 10-19 J.
n = 2
n = 3
n = 4
n = 5
n = 6


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Marked as best answer by jrubin on Nov 18, 2019

missalyssa26

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Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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jrubin

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Reply 2 on: Nov 18, 2019
Thanks for the timely response, appreciate it


vickyvicksss

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Reply 3 on: Yesterday
Gracias!

 

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