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Author Question: Determine the [OH] concentration in a 0.235 mol L-1 NaOH solution. (Read 54 times)

AEWBW

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on: Nov 18, 2019

Question 1

Which of the following bases is the weakest? The base is followed by its Kb value.
◦ CH3CH2NH2, 5.6 × 10-4
◦ NH3, 1.76 × 10-5
◦ HOCH2CH2NH2, 3.2 × 10-5
◦ (CH3CH2)3N, 5.2 × 10-4
◦ C5H5N, 1.7 × 10-9

Question 2

Determine the [OH⁻] concentration in a 0.235 mol L-1 NaOH solution.
◦ 0.198 mol L-1
◦ 0.470 mol L-1
◦ 2.13 × 10-14 mol L-1
◦ 4.25 × 10-14 mol L-1
◦ 0.235 mol L-1
Chemistry: A Molecular Approach (Canadian) ¦ Tro, Fridgen, Shaw ¦ 2nd Edition
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Marked as best answer by AEWBW on Nov 18, 2019

kingfahad97

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Reply #1 on: Nov 18, 2019
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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AEWBW

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Reply 2 on: Nov 18, 2019
Wow, this really help

flexer1n1

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Reply 3 on: Yesterday
YES! Correct, THANKS for helping me on my review

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