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Author Question: Identify the expression for the solubility product constant for PbCl2. (Read 160 times)

newyorker26

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on: Nov 18, 2019

Question 1

Determine the molar solubility of AgBr in a solution containing 0.150 mol L-1 NaBr. Ksp (AgBr) = 7.7 × 10-13.
◦ 5.8 × 10-5 mol L-1
◦ 0.150 mol L-1
◦ 8.8 × 10-7 mol L-1
◦ 5.1 × 10-12 mol L-1
◦ 3.9 × 10-13 mol L-1

Question 2

Identify the expression for the solubility product constant for PbCl2.
◦ [Pb2+][Cl⁻]2
◦ [Pb2+]2[Cl⁻]
◦
◦
◦
Chemistry: A Molecular Approach (Canadian) ¦ Tro, Fridgen, Shaw ¦ 2nd Edition
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Marked as best answer by newyorker26 on Nov 18, 2019

cpetit11

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Reply #1 on: Nov 18, 2019
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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newyorker26

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Reply 2 on: Nov 18, 2019
Great answer, keep it coming :)

ghepp

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Reply 3 on: Yesterday
:D TYSM

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