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Author Question: Use the free energies of formation given below to calculate the equilibrium constant (K) for the ... (Read 113 times)

james

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Question 1

Which of the following reactions will have the largest equilibrium constant (K) at 298 K?
Fe2O3(s) + 3CO(g) → 2Fe(s) + 3CO2(g)ΔrG° = -28.0 kJ mol-1

CaCO3(s) → CaO(s) + CO2(g)ΔrG° =+131.1 kJ mol-1

3O2(g) → 2O3(g)ΔrG° = +326 kJ mol-1

2 Hg(g) + O2(g) → 2HgO(s) ΔrG° = -180.8 kJ mol-1


Question 2

Use the free energies of formation given below to calculate the equilibrium constant (K) for the following reaction at 298 K:

2HNO3(aq) + NO(g) → 3 NO2(g) + H2O(l)K = ?
ΔfG° (kJ mol-1)-110.987.651.3-237.1

◦ 1.15 × 10-9
◦ 5.11 × 10-4
◦ 0.980
◦ 1.02
◦ 8.71 × 108


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Marked as best answer by james on Nov 18, 2019

zogaridan

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james

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Reply 2 on: Nov 18, 2019
Gracias!


essyface1

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Reply 3 on: Yesterday
Great answer, keep it coming :)

 

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