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Author Question: A linear programming problem has three constraints: 2X + 10Y 1004X + 6Y 1206X + 3Y 90What is the ... (Read 42 times)

HCHenry

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on: Dec 3, 2019

Question 1

A firm makes two products, Y and Z. Each unit of Y costs $10 and sells for $40. Each unit of Z costs $5 and sells for $25. If the firm's goal were to maximize profit, the appropriate objective function would be
◦ maximize $40Y = $25Z.
◦ maximize 0.25Y + 0.20Z.
◦ maximize $20Y + $50Z.
◦ maximize $30Y + $20Z.
◦ maximize $40Y + $25Z.

Question 2

A linear programming problem has three constraints:
2X + 10Y ≤ 1004X + 6Y ≤ 1206X + 3Y ≤ 90
What is the largest quantity of X that can be made without violating any of these constraints?
◦ 20
◦ 30
◦ 50
◦ 10
◦ 15
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Marked as best answer by HCHenry on Dec 3, 2019

dellikani2015

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Reply #1 on: Dec 3, 2019
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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HCHenry

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Reply 2 on: Dec 3, 2019
Wow, this really help

Dinolord

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Reply 3 on: Yesterday
Gracias!

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