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Author Question: For a process to be at equilibrium, it is necessary that (Read 25 times)

jc611

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on: Feb 15, 2020

Question 1

The standard molar entropy for Br2(g) is 245.46 J/(mol ∙ K) at 25°C. Given that ΔS° = 104.58 J/K for the dissociation of one mole of Br2(g) into Br(g) at 25°C, find the standard molar entropy for Br(g) at 25°C.
◦ 175.02 J/(mol ∙ K)
◦ 350.04 J/(mol ∙ K)
◦ 140.08 J/(mol ∙ K)
◦ 70.44 J/(mol ∙ K)

Question 2

For a process to be at equilibrium, it is necessary that
◦ ΔSsys = 0 and ΔSsurr = 0.
◦ ΔSsys = ΔSsurr.
◦ ΔSsys = 0.
◦ ΔSsys = -ΔSsurr.
Chemistry ¦ McMurry, Fay, Robinson ¦ 7th Edition
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Marked as best answer by jc611 on Feb 15, 2020

srodz

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Reply #1 on: Feb 15, 2020
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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jc611

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Reply 2 on: Feb 15, 2020
Wow, this really help

ryhom

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Reply 3 on: Yesterday
YES! Correct, THANKS for helping me on my review

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