Question 1
Calculate the cell potential at 25°C for the cell
Fe(s) ∣ (Fe2+(0.100 M) ∣∣ Pd2+(1.0 × 10-5 M) ∣ Pd(s)
given that the standard reduction potential for Fe
2+/Fe is -0.45 V and for Pd
2+/Pd is +0.95 V.
◦ +1.28 V
◦ +1.52 V
◦ +1.68 V
◦ +1.16 V
Question 2
Calculate the cell potential
E at 25°C for the reaction
2 Al(s) + 3 Fe2+(aq) → 2 Al3+(aq) + 3 Fe(s)
given that [Fe
2+] = 0.020 M, [Al
3+] = 0.10 M, and the standard reduction potential is -1.66 V for Al
3+/Al and -0.45 V for Fe
2+/Fe.
◦ +1.03 V
◦ +1.18 V
◦ +1.20 V
◦ +1.17 V