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Author Question: The 100th term in the arithmetic sequence 3, 7, 11, 15, . . . is (Read 276 times)

Pineapplelove6

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on: May 5, 2020

Question 1

The following nine tasks (with completion times given in hours) are all independent: D(3), E(6), F(4), G(1), H(2), and I(4). Using the critical-path algorithm to schedule this project with four processors results in a finishing time of
◦ 9 hours.
◦ 12 hours.
◦ 8 hours.
◦ 10 hours.
◦ none of these

Question 2

The 100th term in the arithmetic sequence 3, 7, 11, 15, . . .  is
◦ 407.
◦ 103.
◦ 403.
◦ 399.
◦ none of these
Excursions in Modern Mathematics ¦ Tannenbaum ¦ 9th Edition
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Marked as best answer by Pineapplelove6 on May 5, 2020

chinwesucks

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Reply #1 on: May 5, 2020
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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Pineapplelove6

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Reply 2 on: May 5, 2020
Wow, this really help

jamesnevil303

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Reply 3 on: Yesterday
:D TYSM

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