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Author Question: Analyze the following code:public class Test { public static void main(String[] args) {int n = 10000 ... (Read 131 times)

MGLQZ

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  • Posts: 579
Analyze the following code:

public class Test {
public static void main(String[] args) {
int n = 10000 * 10000 * 10000;
System.out.println("n is " + n);
}
}

◦ The result of 10000 * 10000 * 10000 is too large to be stored in an int variable n. This causes an overflow and the program is aborted.
◦ The result of 10000 * 10000 * 10000 is too large to be stored in an int variable n. This causes an underflow and the program is aborted.
◦ The result of 10000 * 10000 * 10000 is too large to be stored in an int variable n. This causes an overflow and the program continues to execute because Java does not report errors on overflow.
◦ The result of 10000 * 10000 * 10000 is too large to be stored in an int variable n. This causes an underflow and the program continues to execute because Java does not report errors on underflow.
◦ The program displays n is 1000000000000.


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Marked as best answer by MGLQZ on May 6, 2020

bd5255

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MGLQZ

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Reply 2 on: May 6, 2020
Excellent


tanna.moeller

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  • Posts: 328
Reply 3 on: Yesterday
Gracias!

 

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