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Author Question: Analyze the following statement:double sum = 0;for (double d = 0; d < 10;) { d += 0.1; sum += sum + d;} (Read 94 times)

burton19126

  • Hero Member
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  • Posts: 532
on: May 6, 2020

Question 1

What is the value in count after the following loop is executed?

int count = 0;
do {
System.out.println("Welcome to Java");
} while (count++ < 9);
System.out.println(count);

◦ 8
◦ 9
◦ 10
◦ 11
◦ 0

Question 2

Analyze the following statement:

double sum = 0;
for (double d = 0; d < 10;) {
d += 0.1;
sum += sum + d;
}

◦ The program runs in an infinite loop because d<10 would always be true.
◦ The program compiles and runs fine.
◦ The program has a compile error because the adjustment is missing in the for loop.
◦ The program has a compile error because the control variable in the for loop cannot be of the double type.
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Marked as best answer by burton19126 on May 6, 2020

ecabral0

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Reply #1 on: May 6, 2020
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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burton19126

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  • Posts: 532
Reply 2 on: May 6, 2020
:D TYSM

meow1234

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Reply 3 on: Yesterday
Wow, this really help

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