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Author Question: Analyze the following code.double sum = 0;for (double d = 0; d < 10; sum += sum + d) { d += 0.1;} (Read 198 times)

mp14

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on: May 6, 2020
Analyze the following code.

double sum = 0;
for (double d = 0; d < 10; sum += sum + d) {
d += 0.1;
}

◦ The program has a syntax error because the control variable in the for loop cannot be of the double type.
◦ The program compiles but does not stop because d would always be less than 10.
◦ The program compiles and runs fine.
◦ The program has a syntax error because the adjustment statement is incorrect in the for loop.
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Marked as best answer by mp14 on May 6, 2020

lorealeza

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Reply #1 on: May 6, 2020
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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mp14

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Reply 2 on: May 6, 2020
Excellent

amandanbreshears

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Reply 3 on: Yesterday
Great answer, keep it coming :)

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