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Author Question: Analyze the following code:public class Test extends A { public static void main(String[] args) ... (Read 39 times)

Melani1276

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Analyze the following code:

public class Test extends A {
public static void main(String[] args) {
Test t = new Test();
t.print();
}
}

class A {
String s;

A(String s) {
this.s = s;
}

public void print() {
System.out.println(s);
}
}

◦ The program does not compile because Test does not have a default constructor Test().
◦ The program compiles, but it has a runtime error due to the conflict on the method name print.
◦ The program would compile if a default constructor A(){ } is added to class A explicitly.
◦ The program has an implicit default constructor Test(), but it cannot be compiled, because its super class does not have a default constructor. The program would compile if the constructor in the class A were removed.


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Marked as best answer by Melani1276 on May 6, 2020

stallen

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Melani1276

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  • Posts: 516
Reply 2 on: May 6, 2020
Wow, this really help


JaynaD87

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  • Posts: 368
Reply 3 on: Yesterday
:D TYSM

 

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