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Author Question: A 2.0-kg block slides on a frictionless 25 inclined plane. A force of 4.6 N acting parallel to the ... (Read 233 times)

formula1

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on: Aug 1, 2020
A 2.0-kg block slides on a frictionless 25° inclined plane. A force of 4.6 N acting parallel to the incline and up the incline is applied to the block. What is the acceleration of the block?

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1.8 m/s2 up the incline

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2.3 m/s2 up the incline

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6.6 m/s2 down the incline

◦
1.8 m/s2 down the incline

◦
2.3 m/s2 down the incline
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Marked as best answer by formula1 on Aug 1, 2020

duke02

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Reply #1 on: Aug 1, 2020
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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formula1

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Reply 2 on: Aug 1, 2020
Gracias!

juliaf

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Reply 3 on: Yesterday
Excellent

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