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Author Question: A 7.0-kg block on a horizontal frictionless surface is attached to a light spring (force constant = ... (Read 1023 times)

V@ndy87

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on: Aug 1, 2020

Question 1

A 6.0-kg block slides along a horizontal surface. If µk = 0.20 for the block and surface, at what rate is the friction force changing the mechanical energy of the block at an instant when its speed is 4.0 m/s?

◦
−59 W

◦
−47 W

◦
−71 W

◦
−82 W

◦
+71 W


Question 2

A 7.0-kg block on a horizontal frictionless surface is attached to a light spring (force constant = 1.2 kN/m). The block is initially at rest at its equilibrium position when a force of magnitude P acting parallel to the surface is applied to the block, as shown. When the block is 8.0 cm from the equilibrium position, it has a speed of 0.80 m/s. How much work is done on the block by the force P as the block moves the 8.0 cm?



◦
7.4 J

◦
5.4 J

◦
6.1 J

◦
6.7 J

◦
4.9 J
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Marked as best answer by V@ndy87 on Aug 1, 2020

ebenov

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Reply #1 on: Aug 1, 2020
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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V@ndy87

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Reply 2 on: Aug 1, 2020
Great answer, keep it coming :)

AISCAMPING

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Reply 3 on: Yesterday
Gracias!

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