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Author Question: If M = 0.50 kg, L = 1.2 m, and the mass of each connecting rod shown is negligible, what is the ... (Read 420 times)

Capo

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on: Aug 1, 2020
If M = 0.50 kg, L = 1.2 m, and the mass of each connecting rod shown is negligible, what is the moment of inertia about an axis perpendicular to the paper through the center of mass? Treat the mass as particles.



◦
3.7 kg⋅m2

◦
2.8 kg⋅m2

◦
3.2 kg⋅m2

◦
2.3 kg⋅m2

◦
3.9 kg⋅m2
Physics for Scientists and Engineers ¦ Serway, Jewett ¦ 9th Edition
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Marked as best answer by Capo on Aug 1, 2020

CharlieArnold

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Reply #1 on: Aug 1, 2020
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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Capo

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Reply 2 on: Aug 1, 2020
:D TYSM

bblaney

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Reply 3 on: Yesterday
Gracias!

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