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Author Question: Two charges lie on the x axis, +2q at the origin, and 3q at x = 5.0 m. The point on the x axis where ... (Read 277 times)

hbsimmons88

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on: Aug 6, 2020

Question 1

Through what potential difference must an electron (starting from rest) be accelerated if it is to reach a speed of 3.0 × 107 m/s?

◦
5.8 kV

◦
2.6 kV

◦
7.1 kV

◦
8.6 kV

◦
5.1 kV


Question 2

Two charges lie on the x axis, +2q at the origin, and −3q at x = 5.0 m. The point on the x axis where the electric potential has a zero value (when the value at infinity is also zero) is

◦
1.0 m.

◦
2.0 m.

◦
2.5 m.

◦
3.0 m.

◦
4.0 m.
Physics for Scientists and Engineers ¦ Serway, Jewett ¦ 9th Edition
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Marked as best answer by hbsimmons88 on Aug 6, 2020

connor417

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Reply #1 on: Aug 6, 2020
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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hbsimmons88

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Reply 2 on: Aug 6, 2020
YES! Correct, THANKS for helping me on my review

ricroger

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Reply 3 on: Yesterday
Wow, this really help

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