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Author Question: What is the radius of curvature of the path of a 3.0-keV proton in a perpendicular magnetic field of ... (Read 105 times)

humphriesbr@me.com

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on: Aug 6, 2020

Question 1

What is the magnitude of the magnetic force on a charged particle (Q = 5.0 μC) moving with a speed of 80 km/s in the positive x direction at a point where Bx = 5.0 T, By = −4.0 T, and Bz = 3.0 T?

◦
2.8 N

◦
1.6 N

◦
1.2 N

◦
2.0 N

◦
0.4 N


Question 2

What is the radius of curvature of the path of a 3.0-keV proton in a perpendicular magnetic field of magnitude 0.80 T?

◦
9.9 mm

◦
1.1 cm

◦
1.3 cm

◦
1.4 cm

◦
7.6 mm
Physics for Scientists and Engineers ¦ Serway, Jewett ¦ 9th Edition
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Marked as best answer by humphriesbr@me.com on Aug 6, 2020

cdmart10

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Reply #1 on: Aug 6, 2020
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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humphriesbr@me.com

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Reply 2 on: Aug 6, 2020
Gracias!

ultraflyy23

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Reply 3 on: Yesterday
Great answer, keep it coming :)

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