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Author Question: A person with no more than $4000 to invest plans to place the money in two ... (Read 196 times)

Mollykgkg

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on: Feb 28, 2021
Solve the problem.

A person with no more than $4000 to invest plans to place the money in two investments, telecommunications and pharmaceuticals. The telecommunications investment is to be no more than 3 times the pharmaceuticals investment. Write a system of inequalities to describe the situation. Let to be invested in telecommunications and to be invested in pharmaceuticals.
◦ x + y ≤ 4000
x ≤ 3y
x ≥ 0
y ≥ 0
◦ x + y = 4000
y ≥ 3x
x ≥ 0
y ≥ 0
◦ x + y = 4000
x ≤ 3y
x ≥ 0
y ≥ 0
◦ x + y ≤ 4000
3x ≤ y
x ≥ 0
y ≥ 0
Precalculus ¦ Sullivan ¦ 10th Edition
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Marked as best answer by Mollykgkg on Feb 28, 2021

Natalie4ever

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Reply #1 on: Feb 28, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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Mollykgkg

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Reply 2 on: Feb 28, 2021
Thanks for the timely response, appreciate it

scottmt

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Reply 3 on: Yesterday
:D TYSM

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