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Author Question: Mrs. White wants to crochet hats and afghans for a church ... (Read 197 times)

Kthamas

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on: Feb 28, 2021
Set up the linear programming problem.

Mrs. White wants to crochet hats and afghans for a church fundraising bazaar. She needs 7 hours to make a hat and 2 hours to make an afghan, and she has no more than 56 hours available. She has material for no more than 13 items, and she wants to make at least two afghans. Let x = the number of hats she makes and y = the number of afghans she makes. Write a system of inequalities that describes these constraints.
◦ 2x + 7y ≤ 56
x + y ≤ 13
x ≤ 2
◦ 7x + 2y ≥ 56
x + y ≤ 13
y ≥ 2
◦ 7x + 2y ≤ 56
x + y ≤ 13
x ≥ 2
◦ 7x + 2y ≤ 56
x + y ≤ 13
y ≥ 2
Precalculus ¦ Sullivan ¦ 10th Edition
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Marked as best answer by Kthamas on Feb 28, 2021

ebe

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Reply #1 on: Feb 28, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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Kthamas

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Reply 2 on: Feb 28, 2021
Thanks for the timely response, appreciate it

epscape

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Reply 3 on: Yesterday
:D TYSM

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