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Author Question: For the reaction: AgI(s) + Br2(g) AgBr(s) + I2(s), H = -54.0 kJ Hf for AgBr(s) = -100.4 ... (Read 40 times)

asd123

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on: Mar 21, 2021
For the reaction:

              AgI(s) + Br2(g) → AgBr(s) + I2(s), ΔH° = -54.0 kJ

              ΔHf° for AgBr(s) = -100.4 kJ/mol

              ΔHf° for Br2(g) = +30.9 kJ/mol

The value of ΔHf° for AgI(s) is:


◦ -123.5 kJ/mol.
◦ +77.3 kJ/mol.
◦ +61.8 kJ/mol.
◦ -77.3 kJ/mol.
◦ -61.8 kJ/mol.
Chemistry: An Atoms First Approach ¦ Zumdahl, DeCoste ¦ 3rd Edition
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Marked as best answer by asd123 on Mar 21, 2021

tjayeee

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Reply #1 on: Mar 21, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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asd123

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Reply 2 on: Mar 21, 2021
Excellent

yeungji

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Reply 3 on: Yesterday
Wow, this really help

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