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Author Question: How would you expect the melting point of CF4 to compare to that of RbF? (Read 43 times)

bio_gurl

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Question 1

How much energy is needed to convert 57.2 grams of ice at 0.00°C to water at 75.0°C?
    specific heat (ice) = 2.10 J/g°C
    specific heat (water) = 4.18 J/g°C
    heat of fusion = 333 J/g
    heat of vaporization = 2258 J/g

17.9 kJ
2.05 kJ
28.1 kJ
37.0 kJ
147 kJ

Question 2

How would you expect the melting point of CF4 to compare to that of RbF?

It should be lower because RbF forms an extended ionic crystal lattice, whereas CF4 is a covalently-bonded small molecule.
It should be similar since they are both ionic solids.
It should be higher because the bonds are stronger due to the higher charge on C (+4).
It should be higher because CF4 is larger than RbF.
It is not possible to say anything about their melting points without more information.


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Marked as best answer by bio_gurl on Mar 21, 2021

itsakadoozi

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Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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bio_gurl

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Reply 2 on: Mar 21, 2021
Excellent


patma1981

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Reply 3 on: Yesterday
Wow, this really help

 

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