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Author Question: A 50.0-mL sample of a 1.50 M NaOH solution is titrated with a 3.40 M HCl solution. What will be the ... (Read 142 times)

londonang

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on: Mar 21, 2021

Question 1

A 50.0-mL sample of 0.10 M HNO2 (Ka = 4.0 × 10–4) is titrated with 0.14 M NaOH. The pH after 25.0 mL of NaOH have been added is

◦ 10.23
◦ 7.00
◦ 6.77
◦ 3.77
◦ None of these are correct.

Question 2

A 50.0-mL sample of a 1.50 M NaOH solution is titrated with a 3.40 M HCl solution. What will be the final volume of solution when the NaOH has been completely neutralized by the HCl?

◦ 72.1 mL
◦ 22.1 mL
◦ 57.1 mL
◦ 305 mL
◦ 76.1 mL
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Marked as best answer by londonang on Mar 21, 2021

Juro

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Reply #1 on: Mar 21, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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londonang

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Reply 2 on: Mar 21, 2021
Wow, this really help

alvinum

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Reply 3 on: Yesterday
Great answer, keep it coming :)

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