Author Question: A 0.012-mol sample of Na2SO4 is added to 400 mL of each of two solutions. One solution contains 1.5 ... (Read 138 times)

crazycityslicker · **on:** Mar 21, 2021

Question 1

A solution is prepared from 3.5 × 10²mL of 3.2 M Pb(NO₃)₂ and 2.0×10² mL of 0.020 M NaCl. Given that K_sp for lead chloride is 1.6×10^-5, what is the ion product?

Reference: Ref 16-1

◦ 1.1 × 10^–4
◦ 1.5 × 10^–2
◦ 7.8 × 10^–3
◦ 8.1 × 10^–4
◦ None of these are correct.

Question 2

A 0.012-mol sample of Na₂SO₄ is added to 400 mL of each of two solutions. One solution contains 1.5 × 10^–3M BaCl₂; the other contains 1.5 × 10^–3M CaCl₂. Given that K_sp for BaSO₄ = 1.5 × 10^–9 and K_sp for CaSO₄ = 6.1 × 10^–5:

◦ BaSO₄ would precipitate but CaSO₄ would not.
◦ CaSO₄ would precipitate but BaSO₄ would not.
◦ Both BaSO₄ and CaSO₄ would precipitate.
◦ Neither BaSO₄ nor CaSO₄ would precipitate.
◦ Not enough information is given to determine if precipitation would occur.

jgranad15 · **Reply #1 on:** Mar 21, 2021

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