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Author Question: For a certain process, at 300. K, G = 21.2 kJ and H = 7.0 kJ. If the process is carried out ... (Read 82 times)

bcretired

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on: Mar 21, 2021

Question 1

For a certain process, at 300. K, ΔG = –32.2 kJ and ΔH = –7.0 kJ. If the process is carried out so that no useful work is performed, ΔG is

◦ 32.2 kJ
◦ 7.0 kJ
◦ 0 kJ
◦ –7.0 kJ
◦ –32.2 kJ

Question 2

For a certain process, at 300. K, ΔG = –21.2 kJ and ΔH = –7.0 kJ. If the process is carried out reversibly, the amount of useful work that can be performed is

◦ –28.2 kJ
◦ –7.0 kJ
◦ –14.2 kJ
◦ –21.2 kJ
◦ 14.2 kJ
Chemistry: An Atoms First Approach ¦ Zumdahl, DeCoste ¦ 3rd Edition
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Marked as best answer by bcretired on Mar 21, 2021

raenoj

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Reply #1 on: Mar 21, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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bcretired

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Reply 2 on: Mar 21, 2021
Gracias!

AngeliqueG

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Reply 3 on: Yesterday
YES! Correct, THANKS for helping me on my review

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