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Author Question: A strip of copper is placed in a 1 M solution of copper nitrate and a strip of silver is placed in a ... (Read 86 times)

Deast7027

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Question 1

A solution of MnO42– is electrolytically reduced to Mn3+. A current of 5.29 amp is passed through the solution for 15.0 minutes. What is the number of moles of Mn3+ produced in this process? (1 faraday = 96,485 coulombs)

0.0493 mol
0.148 mol
2.74 × 10–4 mol


0.0164 mol
1.10 × 10–3 mol



Question 2

A strip of copper is placed in a 1 M solution of copper nitrate and a strip of silver is placed in a 1 M solution of silver nitrate. The two metal strips are connected to a voltmeter by wires and a salt bridge connects the solutions. The following standard reduction potentials apply:
 
Ag+(aq) + e Ag(s)
E° = +0.80 V
 
Cu2+(aq) + 2e Cu(s)
E° = +0.34 V
Which of the following statements is false?


Electrons flow in the external circuit from the copper electrode to the silver electrode.
The silver electrode increases in mass as the cell operates.
There is a net general movement of silver ions through the salt bridge to the copper half-cell.
Negative ions pass through the salt bridge from the silver half-cell to the copper half-cell.
Some positive copper ions pass through the salt bridge from the copper half-cell to the silver half-cell.


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Marked as best answer by Deast7027 on Mar 21, 2021

micaelaswann

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Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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Deast7027

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Reply 2 on: Mar 21, 2021
:D TYSM


Perkypinki

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Reply 3 on: Yesterday
Great answer, keep it coming :)

 

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