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Author Question: Describe the region defined by the pair of inequalities x2 + y2 9 and x2 + (y + 3)2 6. (Read 39 times)

waynest

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Question 1

Find the centre and radius of the circle having the equation  x2 + y2 - 12x + 20y + 15 = 0.
◦ centre (6, 10) and radius
◦ centre (-6, 10) and radius  15
◦ centre (6, -10) and radius  121
◦ centre (6, -10) and radius  11
◦ centre (12, -20) and radius  15

Question 2

Describe the region defined by the pair of inequalities  x2 + y2  ≤  9  and  x2 + (y + 3)2  ≤  6.
◦ all points that are inside or on both the circle of radius 3 centred at the origin and the circle of radius centred at (3, 0)
◦ all points that are inside or on both the circle of radius 3 centred at the origin and the circle of radius centred at (-3, 0)
◦ all points that are inside or on both the circle of radius 3 centred at the origin and the circle of radius centred at (0, -3)
◦ all points that are inside or on both the circle of radius 9 centred at the origin and the circle of radius 6 centred at (0, -3)
◦ all points that are inside or on both the circle of radius 3 centred at the origin and the circle of radius centred at (0, 3)


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Marked as best answer by waynest on May 26, 2021

scikid

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Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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waynest

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Reply 2 on: May 26, 2021
Great answer, keep it coming :)


momolu

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Reply 3 on: Yesterday
:D TYSM

 

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