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Author Question: Find the roots of the equation ex = 2e(2x - 1). (Read 47 times)

magmichele12

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  • Posts: 559
on: May 26, 2021

Question 1

Solve the exponential equation 5e2x + 4 = 8  correct to 3 decimal places.
◦ 1.755
◦ 1.693
◦ -1.765
◦ -1.725
◦ 1.735

Question 2

Find the roots of the equation  ex = 2e(2x - 1).
◦ 1
◦ ln(2)
◦ -ln(2)
◦
◦ 1 - ln(2)
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Marked as best answer by magmichele12 on May 26, 2021

aprice35067

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Reply #1 on: May 26, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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magmichele12

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  • Posts: 559
Reply 2 on: May 26, 2021
Wow, this really help

ecabral0

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Reply 3 on: Yesterday
Gracias!

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