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Author Question: In a classical equation from chemistry, the pressure of a gas is proportional to the product of the ... (Read 118 times)

Diane

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on: May 26, 2021
In a classical equation from chemistry, the pressure of a gas is proportional to the product of the volume of the gas and the temperature of the gas. In symbols, P = kVT for some constant k. How fast is the pressure changing at an instant when the volume is 20 mL and increasing at 3 mL/min and the temperature is at 21 degrees C and is decreasing at a rate of 2 degrees per minute? Assume that k = 0.8 kilograms per mL-degree.
◦ decreasing at 23.5 kilograms/min
◦ increasing at 18.4 kilograms/min
◦ increasing at 12.7 kilograms/min
◦ decreasing at 12.8 kilograms/min
◦ increasing at 14.4 kilograms/min
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Marked as best answer by Diane on May 26, 2021

jharrington11

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Reply #1 on: May 26, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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Diane

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Reply 2 on: May 26, 2021
Gracias!

robbielu01

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Reply 3 on: Yesterday
Wow, this really help

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