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Author Question: The limit represents the area of a certain region in the xy-plane. Describe the region. (Read 101 times)

stevenposner

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on: May 26, 2021

Question 1

Given that =  2,  find the area under  y = x3  and above the interval  [0, a]  on the x-axis  (where  a > 0 )  by interpreting the area as a limit of a suitable sum.
◦  square units
◦  square units
◦  square units
◦  square units
◦  square units

Question 2

The limit represents the area of a certain region in the xy-plane. Describe the region.
◦ region under  y = sin x,  above  y = 0,  between x = 0  and  x =
◦ region under  y = cos x,  above  y = 0,  between x= and  x = π
◦ region under  y = cos x,  above  y = 0,  between x = 0  and  x =
◦ region under  y = sin x,  above  y = 0,  between x = 0  and  x = π
◦ region under  y = cos x,  above  y = 0,  between x = 0  and  x = π
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Marked as best answer by stevenposner on May 26, 2021

nixon_s

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Reply #1 on: May 26, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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stevenposner

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Reply 2 on: May 26, 2021
YES! Correct, THANKS for helping me on my review

ttt030911

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Reply 3 on: Yesterday
Thanks for the timely response, appreciate it

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