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Author Question: Determine the solution of the differential equation = (1 - 2x)y2 that satisfies the condition y(0) = - . (Read 93 times)

ericka1

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on: May 26, 2021

Question 1

Find the solution of the initial-value problem   = 3(x + 2)3, y(0) = 0.
◦ y = - (x + 2)4 + 12
◦ y = (x + 2)3 -
◦ y = 9 (x + 2)2 - 36
◦ y = (x + 2)4 - 12
◦ y = 3 (x + 2)2 - 48

Question 2

Determine the solution of the differential equation = (1 - 2x)y2  that satisfies the condition  y(0) = - .
◦ y =
◦ y =
◦ y =
◦ y =
◦ y =
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Marked as best answer by ericka1 on May 26, 2021

pangili4

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Reply #1 on: May 26, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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ericka1

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Reply 2 on: May 26, 2021
Excellent

Dominic

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Reply 3 on: Yesterday
Gracias!

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