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Author Question: Find an equation of the plane tangent to the surface z = x2 - y2 at the point (2, 1, 3). (Read 98 times)

ENagel

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on: May 27, 2021

Question 1

Find the slope of the tangent line to the curve that is the intersection  of the surface  z = x2 - y2  with the plane x = 2 at the point (2, 1, 3).
◦ 2
◦ -2
◦ -4
◦ 0
◦ 4

Question 2

Find an equation of the plane tangent to the surface  z = x2 - y2  at the point  (2, 1, 3).
◦ 4x + 2y + z = 13
◦ 4x - 2y + z = -9
◦ 4x - 2y + z = 9
◦ 4x - 2y - z = 3
◦ 4x + 2y - z = 7
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Marked as best answer by ENagel on May 27, 2021

tranoy

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Reply #1 on: May 27, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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ENagel

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Reply 2 on: May 27, 2021
Great answer, keep it coming :)

bimper21

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Reply 3 on: Yesterday
:D TYSM

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