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Author Question: Find the point on the surface z = x2 + y2 closest to the point (1, 1, 0). (Read 88 times)

savannahhooper

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on: May 27, 2021

Question 1

Use Lagrange multipliers to find the maximum and minimum values of the function  on the sphere
◦ maximum  12,   minimum  -12
◦ maximum  6,   minimum  -6
◦ maximum  12,  minimum  -12
◦ maximum  6,   minimum  -6
◦ maximum  6,   minimum  -6

Question 2

Find the point  on the surface z = x2 + y2  closest to the point (1, 1, 0).
◦
◦
◦ (1, 1, 1)
◦
◦
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Marked as best answer by savannahhooper on May 27, 2021

dlook33

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Reply #1 on: May 27, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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savannahhooper

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Reply 2 on: May 27, 2021
YES! Correct, THANKS for helping me on my review

bigcheese9

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Reply 3 on: Yesterday
Great answer, keep it coming :)

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