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Author Question: Solve the initial-value problem 12y" - y' -6y = 0; y(0) = 2, y'(0) = 10. (Read 130 times)

strangeaffliction

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Question 1

Find the general solution of the differential equation  12y" + 13y' + 3y = 0.
◦ y = c1 e-3t/4 + c2 e-t/3
◦ y = c1 e-3t/4 - c2 et/3
◦ y = c1 e3t/4 + c2 et/3
◦ y = c1 e3t/4 + c2 e-t/3
◦ y = c1 e-t/4 + c2 e-t/3

Question 2

Solve the initial-value problem 12y" - y' -6y = 0;  y(0) = 2,  y'(0) = 10.
◦ y(t) = 4 e-2t/3 - 2 e3t/4
◦ y(t) = -6 e-2t/3 + 8 e3t/4
◦ y(t) = -6 e2t/3 + 8 e-3t/4
◦ y(t) = 6 e-2t/3 - 8 e3t/4
◦ y(t) = -4 e-2t/3 + 6 e3t/4


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Marked as best answer by strangeaffliction on May 27, 2021

kmb352

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strangeaffliction

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Reply 2 on: May 27, 2021
Great answer, keep it coming :)


dantucker

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Reply 3 on: Yesterday
:D TYSM

 

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