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Author Question: Which of the following gives the balanced equation for this reaction? K3PO4 + Ca(NO3)2 Ca3(PO4)2 + KNO3 (Read 63 times)

tnt_battle

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Question 1

In any balanced chemical equation, the number of each type of atom on both sides of the equation is ________.
◦ decreased by one
◦ increased by one
◦ dependent on the temperature
◦ the same
◦ doubled

Question 2

Which of the following gives the balanced equation for this reaction?

K3PO4 + Ca(NO3)2 → Ca3(PO4)2 + KNO3

◦ 2K3PO4 + 3Ca(NO3)2 → Ca3(PO4)2 + 6KNO3
◦ K3PO4 + Ca(NO3)2 → Ca3(PO4)2 + KNO3
◦ K3PO4 + Ca(NO3)2 → Ca3(PO4)2 + 3KNO3
◦ KPO4 + CaNO3 + KNO3
◦ 2 K3PO4 + Ca(NO3)2 → Ca3(PO4)2 + 6KNO3


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Marked as best answer by tnt_battle on Jun 7, 2021

fromAlphatoOmega22

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Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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tnt_battle

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Reply 2 on: Jun 7, 2021
Gracias!


Sarahjh

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Reply 3 on: Yesterday
:D TYSM

 

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