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Author Question: Evaluate or determine that the limit does not exist for each of the limitsandfor the given function ... (Read 70 times)

chandani

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on: Jun 16, 2021

Question 1

In the exercise below, the initial substitution of x = a yields the form 0/0. Look for ways to simplify the function algebraically, or use a table and/or graph to determine the limit. When necessary, state that the limit does not exist.

 
◦ 4
◦ 0
◦
◦

Question 2

Evaluate or determine that the limit does not exist for each of the limits   and  for the given function f and number d.

f(x) = ;  d = -4
◦ (a) 2
(b) 4
(c) Does not exist
◦ (a) 18
(b) 18
(c) 18
◦ (a) 2
(b) 4
(c) 4
◦ (a) 4
(b) 2
(c) Does not exist
Calculus and Its Applications ¦ Bittinger, Ellenbogen, Surgent ¦ 11th Edition
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Marked as best answer by chandani on Jun 16, 2021

BAOCHAU2803

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Reply #1 on: Jun 16, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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chandani

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Reply 2 on: Jun 16, 2021
Great answer, keep it coming :)

cpetit11

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Reply 3 on: Yesterday
YES! Correct, THANKS for helping me on my review

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