Write the net ionic equation for the reaction of lead(II) nitrate and sodium iodide.
◦ Pb(NO3)2(aq) + 2 NaI(aq) → PbI2(s) + 2 NaNO3(aq)
◦ Pb2+(aq)+ 2 NaI(aq) → PbI2(s) + 2 Na
◦ Pb2+(aq)+ 2 I-(aq)→ PbI2(s)
◦ Pb2+(aq)+ 2 I-(aq)→ Pb2+(aq)+ 2 I-(aq)
◦ no reaction