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Author Question: A 12-inch diameter ball of pure cobalt metal at 225 C was placed in 10.0 gal. of water at 15.0 C. ... (Read 53 times)

crazycityslicker

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on: Jul 8, 2021
A 12-inch diameter ball of pure cobalt metal at 225 °C was placed in 10.0 gal. of water at 15.0 °C. What is the final temperature of the water? Assume no heat is lost to the surroundings. (specific heat for cobalt is 0.421 J/g °C, density of cobalt = 8.862 g/cm3, 1 gal. = 3.785 L, 1 in = 2.54 cm, V(sphere) = 4/3 πr3)
◦ 169 °C
◦ 120 °C
◦ 69.5 °C
◦ 22.5 °C
◦ 45.6 °C
General Chemistry: Principles and Modern Applications ¦ Petrucci, Herring, Madura, Bissonnette ¦ 11th Edition
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Marked as best answer by crazycityslicker on Jul 8, 2021

tranoy

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Reply #1 on: Jul 8, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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crazycityslicker

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Reply 2 on: Jul 8, 2021
Wow, this really help

phuda

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Reply 3 on: Yesterday
Excellent

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