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Author Question: For the reaction H2(g) + 1/2 O2(g) H2O(g) rH = -241.8 kJ/mol, what quantity of heat, in kJ, evolved ... (Read 38 times)

armygirl

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on: Jul 8, 2021

Question 1

For the reaction H2(g) + 1/2 O2(g) → H2O(g) ΔrH° = -241.8 kJ/mol,
what quantity of heat is liberated by the reaction of 10.0 L of O2 measured at 22.0 °C and 742 mmHg?
◦ 120 kJ
◦ 2610 kJ
◦ 1310 kJ
◦ 195 kJ
◦ 97.5 kJ

Question 2

For the reaction H2(g) + 1/2 O2(g) → H2O(g) ΔrH° = -241.8 kJ/mol,
what quantity of heat, in kJ, evolved when a 72.0 g mixture containing equal parts of H2 and O2, by mass, is burned?
◦ 8630 kJ
◦ 4860 kJ
◦ 1088 kJ
◦ 272 kJ
◦ 544 kJ
General Chemistry: Principles and Modern Applications ¦ Petrucci, Herring, Madura, Bissonnette ¦ 11th Edition
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Marked as best answer by armygirl on Jul 8, 2021

matt95

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Reply #1 on: Jul 8, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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armygirl

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Reply 2 on: Jul 8, 2021
Thanks for the timely response, appreciate it

strudel15

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Reply 3 on: Yesterday
Excellent

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