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Author Question: The equilibrium constant, Kp, equals 3.40 for the isomerization reaction: cis-2-butene ... (Read 56 times)

bobbie

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on: Jul 8, 2021
The equilibrium constant, Kp, equals 3.40 for the isomerization reaction:

cis-2-butene trans-2-butene

If a flask initially contains 0.250 bar of cis-2-butene and 0.165 bar of trans-2-butene, what is the equilibrium pressure of each gas?
◦ P(cis-2-butene) = 0.0485 bar and P(trans-2-butene) = 0.165 bar
◦ P(cis-2-butene) = 0.0458 bar and P(trans-2-butene) = 0.156 bar
◦ P(cis-2-butene) = 0.0735 bar and P(trans-2-butene) = 0.250 bar
◦ P(cis-2-butene) = 0.0943 bar and P(trans-2-butene) = 0.321 bar
General Chemistry: Principles and Modern Applications ¦ Petrucci, Herring, Madura, Bissonnette ¦ 11th Edition
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Marked as best answer by bobbie on Jul 8, 2021

dantucker

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Reply #1 on: Jul 8, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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bobbie

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Reply 2 on: Jul 8, 2021
Gracias!

sultana.d

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Reply 3 on: Yesterday
:D TYSM

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