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Author Question: What is the [H2AsO4-] for an aqueous solution labeled "0.10 M arsenic acid (H3AsO4)"? [Ka1 = 6 ... (Read 33 times)

jerry coleman

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on: Jul 8, 2021

Question 1

What is the [Cl-] of a solution prepared by dissolving 0.1824 g of hydrogen chloride in sufficient pure water to prepare 500.0 ml of solution?
◦ 1.00 × 10-2 M
◦ 1.00 × 10-8 M
◦ 1.00 × 10-12 M
◦ 1.00 × 10-4 M
◦ 1.0 M

Question 2

What is the [H2AsO4-] for an aqueous solution labeled "0.10 M arsenic acid (H3AsO4)"?

[Ka1 = 6 × 10-3, Ka2 = 1 × 10-7, Ka3 = 3 × 10-12]

◦ 1 × 10-7 M
◦ 6 × 10-3 M
◦ 0.02 M
◦ 0.08 M
◦ 6 × 10-10 M
General Chemistry: Principles and Modern Applications ¦ Petrucci, Herring, Madura, Bissonnette ¦ 11th Edition
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Marked as best answer by jerry coleman on Jul 8, 2021

akudia

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Reply #1 on: Jul 8, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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jerry coleman

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Reply 2 on: Jul 8, 2021
YES! Correct, THANKS for helping me on my review

matt95

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Reply 3 on: Yesterday
Excellent

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