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Author Question: Ten milliliters of 0.10 M NH3(aq) (Kb = 1.8 10-5) is mixed with 10 mL of 0.10 M NH4Cl(aq). ... (Read 30 times)

Mr.Thesaxman

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on: Jul 8, 2021
Ten milliliters of 0.10 M NH3(aq) (Kb = 1.8 × 10-5) is mixed with 10 mL of 0.10 M NH4Cl(aq). Neglecting the differences between activities and concentrations, the resulting solution:
◦ has a pH = 4.74
◦ has a [H+] of approximately 10-3 M
◦ has a [NH4+] greater than that of the NH4Cl(aq)
◦ has an [OH-] of 1.8 × 10-5 M
◦ is acidic
General Chemistry: Principles and Modern Applications ¦ Petrucci, Herring, Madura, Bissonnette ¦ 11th Edition
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Marked as best answer by Mr.Thesaxman on Jul 8, 2021

quynhmickitran

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Reply #1 on: Jul 8, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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Mr.Thesaxman

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Reply 2 on: Jul 8, 2021
Wow, this really help

vickybb89

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Reply 3 on: Yesterday
Gracias!

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