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Author Question: Hydrogen iodide decomposes at 800 K via a second-order process to produce hydrogen and iodine ... (Read 38 times)

stephzh

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on: Jul 8, 2021
Hydrogen iodide decomposes at 800 K via a second-order process to produce hydrogen and iodine according to the following chemical equation:

2 HI(g) → H2(g) + I2(g)

At 800 K it takes 142 seconds for the initial concentration of HI to decrease from 6.75 × 10-2 mol L-1 to 3.50 × 10-2 mol L-1. What is the rate constant for the reaction at this temperature?
◦ 5.12 × 10-4 L mol-1 s-1
◦ 9.69 × 10-2 L mol-1 s-1
◦ 10.3 L mol-1 s-1
◦ 1.95 × 103 L mol-1 s-1
General Chemistry: Principles and Modern Applications ¦ Petrucci, Herring, Madura, Bissonnette ¦ 11th Edition
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Marked as best answer by stephzh on Jul 8, 2021

mceravolo

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Reply #1 on: Jul 8, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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stephzh

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Reply 2 on: Jul 8, 2021
Excellent

patma1981

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Reply 3 on: Yesterday
Thanks for the timely response, appreciate it

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