QUADRATICS: Find vertex from factored form without changing the form?

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Author Question: QUADRATICS: Find vertex from factored form without changing the form? (Read 3538 times)

camila

Hero Member
Posts: 705

on: Jun 17, 2013

how do I find the vertex of this without changing the form?

f(x)= -0.7(1.1-x)(3.2+x)

Jones

Full Member
Posts: 145

Reply #1 on: Jun 17, 2013

1) find the roots:
x= 1.1
x=-3.2

The axis of symmetry is x= (1.1 - 3.2) /2= -1.05
So the x coordinate of the vertex is -1.05

Sub x= -2.1 into f(x), and you'll get the y coordinate of the vertex.

So the vertex is (-1.05, f(-1.05) )

I think you can continue from there....

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Hawke

Hero Member
Posts: 679

Reply #2 on: Jun 18, 2013

the roots are 1.1 , - 3.2

so the vertex must be x = [1.1 + (-3.2)] / 2 = - 1.05 ( in the middle)

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