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Author Question: A BASE jumper's velocity (in meters per second) after t seconds is given by where m is the mass of ... (Read 422 times)

xroflmao

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on: Dec 18, 2021
A BASE jumper's velocity (in meters per second) after t seconds is given by where m is the mass of the object in kilograms, g = 9.8 m/s2 is the acceleration due to gravity, and k is a physical constant. How fast is the BASE jumper falling at the end of a 12 second delay? Use and Round the answer to one decimal place if necessary.
◦ 58.2 m/s
◦ 698 m/s
◦ 63.2 m/s
◦ 19.2 m/s
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Marked as best answer by xroflmao on Dec 18, 2021

meltdown117

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Reply #1 on: Dec 18, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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xroflmao

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Reply 2 on: Dec 18, 2021
Excellent

pratush dev

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Reply 3 on: Yesterday
Thanks for the timely response, appreciate it

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