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Author Question: The position of an object in free fall near the surface of the plane where the acceleration due to ... (Read 208 times)

lidoalex

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on: Dec 18, 2021
The position of an object in free fall near the surface of the plane where the acceleration due to gravity has a constant magnitude of g (length-units)/sec2 is given by the equation:
s = -gt2 + v0t + s0,   where s is the height above the earth, v0 is the initial velocity, and s0 is the initial height.  Give the initial value problem for this situation.  Solve it to check its validity.  Remember the positive direction is the upward direction.
◦ = g ,  s '(0) = v0,   s(0) = s0
◦ = -gt ,  s(0) = s0
◦ = -g ,  s '(0) = v0,   s(0) = s0
◦ = -g
Calculus: Early Transcendentals ¦ Briggs, Cochran, Gillett, Schulz ¦ 3rd Edition
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Marked as best answer by lidoalex on Dec 18, 2021

kaillie

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Reply #1 on: Dec 18, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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lidoalex

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Reply 2 on: Dec 18, 2021
Gracias!

ebonylittles

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Reply 3 on: Yesterday
:D TYSM

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