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Author Question: Select the best explanation for why methanol, CH3OH, cannot be used as a solvent for the ... (Read 63 times)

markburs

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on: Feb 17, 2022
Select the best explanation for why methanol, CH3OH, cannot be used as a solvent for the deprotonation of a terminal alkyne by sodium amide, NaNH2.
◦ Sodium amide is not a strong enough base to deprotonate the alkyne.
◦ Methanol is toxic and should be avoided when possible.
◦ Methanol is more acidic than the alkyne and will be deprotonated by NaNH2.
◦ Methanol is a poor solvent for dissolving alkynes.
◦ Sodium amide in methanol reduces alkynes to alkenes.
Organic Chemistry ¦ Klein ¦ 4th Edition
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Marked as best answer by markburs on Feb 17, 2022

Harsh06

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Reply #1 on: Feb 17, 2022
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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markburs

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Reply 2 on: Feb 17, 2022
Wow, this really help

meow1234

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Reply 3 on: Yesterday
Thanks for the timely response, appreciate it

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