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Author Question: 0.375 g of a monoprotic acid (MW = 245 g/mol) is dissolved in water to produce 25.0 mL of a solution ... (Read 407 times)

cdr_15

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on: Jul 8, 2021

Question 1

0.272 g of a monoprotic acid (MW = 189 g/mol) is dissolved in water to produce 25.0 mL of a solution with pH = 4.93. Determine the ionization constant of the acid.
◦ 4.1 × 10-8
◦ 1.4 × 10-10
◦ 2.1 × 10-4
◦ 2.8 × 10-7
◦ 2.4 × 10-9

Question 2

0.375 g of a monoprotic acid (MW = 245 g/mol) is dissolved in water to produce 25.0 mL of a solution with pH = 3.28. Determine the ionization constant of the acid.
◦ 8.56 × 10-3
◦ 4.5 × 10-6
◦ 7.4 × 10-5
◦ 4.5 × 10-3
◦ 2.3 × 10-2
General Chemistry: Principles and Modern Applications ¦ Petrucci, Herring, Madura, Bissonnette ¦ 11th Edition
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Marked as best answer by cdr_15 on Jul 8, 2021

raenoj

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Reply #1 on: Jul 8, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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olivia xie

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Reply #2 on: Feb 19, 2022
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